(4x^3-8x^2+1)-(4x^3-1)=

Solution for (4x^3-8x^2+1)-(4x^3-1)= equation:

Simplifying
(4x3 + -8x2 + 1) + -1(4x3 + -1) = 0

Reorder the terms:
(1 + -8x2 + 4x3) + -1(4x3 + -1) = 0

Remove parenthesis around (1 + -8x2 + 4x3)
1 + -8x2 + 4x3 + -1(4x3 + -1) = 0

Reorder the terms:
1 + -8x2 + 4x3 + -1(-1 + 4x3) = 0
1 + -8x2 + 4x3 + (-1 * -1 + 4x3 * -1) = 0
1 + -8x2 + 4x3 + (1 + -4x3) = 0

Reorder the terms:
1 + 1 + -8x2 + 4x3 + -4x3 = 0

Combine like terms: 1 + 1 = 2
2 + -8x2 + 4x3 + -4x3 = 0

Combine like terms: 4x3 + -4x3 = 0
2 + -8x2 + 0 = 0
2 + -8x2 = 0

Solving
2 + -8x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -8x2 = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -8x2 = 0 + -2
-8x2 = 0 + -2

Combine like terms: 0 + -2 = -2
-8x2 = -2

Divide each side by '-8'.
x2 = 0.25

Simplifying
x2 = 0.25

Take the square root of each side:
x = {-0.5, 0.5}